2[2(x+1)+1]=14

Solution for 2[2(x+1)+1]=14 equation:

Simplifying
2[2(x + 1) + 1] = 14

Reorder the terms:
2[2(1 + x) + 1] = 14
2[(1 * 2 + x * 2) + 1] = 14
2[(2 + 2x) + 1] = 14

Reorder the terms:
2[2 + 1 + 2x] = 14

Combine like terms: 2 + 1 = 3
2[3 + 2x] = 14
[3 * 2 + 2x * 2] = 14
[6 + 4x] = 14

Solving
6 + 4x = 14

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + -6 + 4x = 14 + -6

Combine like terms: 6 + -6 = 0
0 + 4x = 14 + -6
4x = 14 + -6

Combine like terms: 14 + -6 = 8
4x = 8

Divide each side by '4'.
x = 2

Simplifying
x = 2